develloper et reduire: c= (7t+3)(t-4)-(t-2)(t+6) d= 2x(8x-1)-(4x-5)(4x-1) expliquez moi svp.
Mathématiques
leabourgarit1
Question
develloper et reduire:
c= (7t+3)(t-4)-(t-2)(t+6)
d= 2x(8x-1)-(4x-5)(4x-1)
expliquez moi svp.
c= (7t+3)(t-4)-(t-2)(t+6)
d= 2x(8x-1)-(4x-5)(4x-1)
expliquez moi svp.
1 Réponse
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1. Réponse maran310
Tu dois utiliser la double distributivité:
C= (7t+3) (t-4) - (t-2) (t+6)
C= 7t² -28t +3t -12 - [ t² +6t -2t -12 ]
C= 7t² -28t +3t -12 -t² -6t +2t +12
C= 6t² -29t
D= 2x (8x-1) - (4x-5) (4x-1)
D= 16x² -2x - [ 16x² -4x -20x +5 ]
D= 16x² -2x -16x² +4x +20x -5
D= 22x -5