Factoriser une expression littérale a. 3(x+1) + 5(x+1) b. 2x(y-2) + (y-2)x c. 7(2x + 3) + x²(2x+3) d. -16(x-6) - 8y(x-6) e. -10a(y+7) - (y+7) fois 6a f. x²(x+2)
Mathématiques
haycelemsiaufém
Question
Factoriser une expression littérale
a. 3(x+1) + 5(x+1)
b. 2x(y-2) + (y-2)x
c. 7(2x + 3) + x²(2x+3)
d. -16(x-6) - 8y(x-6)
e. -10a(y+7) - (y+7) fois 6a
f. x²(x+2) + 2(x+2)
a. 3(x+1) + 5(x+1)
b. 2x(y-2) + (y-2)x
c. 7(2x + 3) + x²(2x+3)
d. -16(x-6) - 8y(x-6)
e. -10a(y+7) - (y+7) fois 6a
f. x²(x+2) + 2(x+2)
2 Réponse
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1. Réponse nathalienouts
a. 3(x+1) + 5(x+1)
= (x+1) (3+5)
= 8(x+1)
b. 2x(y-2) + (y-2)x
= (y-2)(2x+x)
= 3x(y-2)
c. 7(2x + 3) + x²(2x+3)
= (2x+3)(7+x²)
d. -16(x-6) - 8y(x-6)
= (x-6)(-16-8y)
= 8(x-6)(-2-y)
e. -10a(y+7) - (y+7) fois 6a
= (y+7)(-10a-6a)
= (y+7)(-16a)
f. x²(x+2) + 2(x+2)
= (x+2)(x²+2) -
2. Réponse laetitialecomte
a. 3(x+1) + 5(x+1)
= (x+1) (3+5)
= 8(x+1)
b. 2x(y-2) + (y-2)x
= (y-2)(2x+x)
= 3x(y-2)
c. 7(2x + 3) + x²(2x+3)
= (2x+3)(7+x²)
d. -16(x-6) - 8y(x-6)
= (x-6)(-16-8y)
= 8(x-6)(-2-y)
e. -10a(y+7) - (y+7) fois 6a
= (y+7)(-10a-6a)
= (y+7)(-16a)
f. x²(x+2) + 2(x+2)
= (x+2)(x²+2)